全純:在開集上可導
若函數在開集 U 的每一點都 複可導,就稱它在 U 上 [[holomorphic-function|全純]]。「開」這個字很關鍵:單點可導幾乎無用,但在整個鄰域上可導就能引出一連串定理。在整個 C 上全純的函數稱為 [[entire-function|整函數]]——多項式、exp(z)、sin(z)、cos(z) 都是整函數。
沿曲線積分
[[contour-integral|圍道積分]] 是把 f 沿一條路徑積分。用 z = γ(t)(t 屬於 [a, b])參數化光滑曲線 γ,然後定義 ∫_γ f(z) dz = ∫_a^b f(γ(t)) γ'(t) dt——這就是一個關於實變量 t 的複值函數的普通積分。因子 γ'(t) 就是鏈式法則給出的「dz」。只要保持方向不變,積分值與參數化方式無關。
Workhorse computation: integrate z^n around the unit circle.
Let gamma(t) = e^{i t}, t in [0, 2*pi]. Then gamma'(t) = i e^{i t}.
integral_gamma z^n dz
= integral_0^{2pi} (e^{i t})^n * (i e^{i t}) dt
= i * integral_0^{2pi} e^{i (n+1) t} dt.
Case n = -1:
= i * integral_0^{2pi} e^{0} dt = i * (2*pi) = 2*pi*i.
Case n != -1 (integer):
integral_0^{2pi} e^{i m t} dt = [ e^{i m t} / (i m) ]_0^{2pi}
= ( e^{i m 2pi} - 1 ) / (i m) = (1 - 1)/(i m) = 0, m = n+1 != 0.
So the integral is 0.
Result: integral over |z|=1 of z^n dz = 2*pi*i if n = -1, else 0.ML 估計
複分析裡幾乎每個證明都用到一個界,即 ML 不等式:若在 γ 上 |f(z)| ≤ M,且 γ 長為 L,則 |∫_γ f dz| ≤ M·L。它直接來自積分的 三角不等式。正是這一個 估計,讓我們能透過把界 M 或長度 L 變小來斷定積分很小。
ML inequality and its proof sketch.
Claim: | integral_gamma f(z) dz | <= M * L,
where M = max over gamma of |f|, and L = length(gamma).
Proof. | integral_a^b f(gamma(t)) gamma'(t) dt |
<= integral_a^b | f(gamma(t)) | * | gamma'(t) | dt (triangle ineq. for integrals)
<= M * integral_a^b | gamma'(t) | dt
= M * L, since integral_a^b |gamma'(t)| dt = arclength = L. QED
Sample use: bound integral over |z|=2 of 1/(z^2+1) dz.
On |z| = 2: |z^2 + 1| >= |z|^2 - 1 = 4 - 1 = 3, so |1/(z^2+1)| <= 1/3 = M.
Length L = 2*pi*2 = 4*pi.
Hence | integral | <= (1/3)(4*pi) = 4*pi/3. (a crude but valid bound)