一套總能收尾的流程
真實的方程式很少以友好的 3x + 5 = 20 形式出現。它們兩邊都有變數、有括號、有分數。好消息是:一套固定流程能搞定所有這些。目標始終不變——孤立變數,讓最後一行寫成 x = 某個數。
兩邊都有變數
當未知數出現在兩邊時,把它集中到能讓係數為正的那一邊——這個小選擇能讓你後面少犯一個符號錯誤。然後照常完成。
Solve 5x - 4 = 2x + 11 Move 2x to the left (subtract 2x from both sides): 5x - 2x - 4 = 11 3x - 4 = 11 Move the -4 (add 4 to both sides): 3x = 15 Divide by 3: x = 5 Check: left 5(5) - 4 = 21; right 2(5) + 11 = 21. 21 = 21 TRUE.
括號與分數
括號用分配律去掉:2(x - 3) = 2x - 6。當括號前是減號時要小心——-(x - 3) 會把兩個符號都翻轉成 -x + 3。分數最好一開始就用清分母去掉:每一項都乘以公分母,這樣就能用整數運算。
Solve (x/2) + (x/3) = 5 LCD of 2 and 3 is 6. Multiply EVERY term by 6: 6*(x/2) + 6*(x/3) = 6*5 3x + 2x = 30 Combine like terms: 5x = 30 Divide by 5: x = 6 Check: 6/2 + 6/3 = 3 + 2 = 5 TRUE.