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Collisions: Elastic and Inelastic

Momentum is always conserved in a collision — but kinetic energy is not. That single distinction sorts every collision into elastic, inelastic, and perfectly inelastic. We derive the elastic-collision formulas, meet the coefficient of restitution, and solve a real problem.

Two questions, one answer each

For any collision, ask two questions. First: is momentum conserved? If the system is isolated, yes, always — we proved that last guide. Second: is kinetic energy conserved? Here the answer varies, and it is exactly what classifies the collision.

An elastic collision conserves kinetic energy too — nothing is lost to heat, sound, or deformation. Two billiard balls, or gas molecules, come very close. An inelastic collision loses some kinetic energy. The extreme case, a perfectly inelastic collision, is when the objects stick together afterward, which loses the most kinetic energy allowed while still conserving momentum.

Perfectly inelastic: they stick

The perfectly inelastic case is the easiest to solve, because after the collision the two masses share a single common velocity. Momentum conservation gives it in one step.

m_1 v_{1i} + m_2 v_{2i} = (m_1 + m_2)\,v_f \;\Longrightarrow\; v_f = \frac{m_1 v_{1i} + m_2 v_{2i}}{m_1 + m_2}

Perfectly inelastic collision: the combined mass moves at the momentum-weighted average of the initial velocities.

How much kinetic energy vanished? Work it out and a clean result appears: the loss depends on the masses and their relative velocity. That lost energy did not disappear — it became heat, sound, and permanent deformation. The physics of a car's crumple zone is deliberately maximizing this loss to protect passengers.

\Delta K = -\frac{1}{2}\,\frac{m_1 m_2}{m_1 + m_2}\,(v_{1i} - v_{2i})^2

Kinetic energy lost in a perfectly inelastic collision. It vanishes only if the relative velocity is zero — that is, if there was no real collision at all.

Elastic collisions in one dimension

An elastic collision gives you two equations — momentum conservation and kinetic-energy conservation — for two unknowns, the final velocities. The algebra is fiddly, but a beautiful shortcut cuts through it: for an elastic collision, the relative velocity reverses. The objects separate exactly as fast as they approached.

v_{1i} - v_{2i} = -\,(v_{1f} - v_{2f})

The elastic-collision shortcut: relative speed of approach equals relative speed of separation. Pair this with momentum conservation to solve without touching the quadratic energy equation.

Solving the pair gives the final velocities in closed form:

v_{1f} = \frac{m_1 - m_2}{m_1 + m_2}\,v_{1i} + \frac{2 m_2}{m_1 + m_2}\,v_{2i}, \qquad v_{2f} = \frac{2 m_1}{m_1 + m_2}\,v_{1i} + \frac{m_2 - m_1}{m_1 + m_2}\,v_{2i}

The one-dimensional elastic-collision formulas. Memorizing the relative-velocity shortcut instead is often faster and less error-prone.

Read off the limiting cases, which build deep intuition. Equal masses (m_1 = m_2): the objects simply exchange velocities — this is the trick behind a Newton's cradle. A heavy object hits a light one at rest: the heavy one barely slows, the light one shoots off at nearly twice the incoming speed. A light object hits a heavy one at rest: the light one bounces almost straight back, the heavy one barely stirs — like a ball off a wall.

The spectrum: coefficient of restitution

Real collisions live between the perfectly elastic and perfectly sticky extremes. The coefficient of restitution e is the single number that places a collision on that spectrum: it is the ratio of relative speed after to relative speed before.

e = \frac{\text{relative speed of separation}}{\text{relative speed of approach}} = -\,\frac{v_{1f} - v_{2f}}{v_{1i} - v_{2i}}

Coefficient of restitution. e = 1 is perfectly elastic (relative velocity reverses fully); e = 0 is perfectly inelastic (they move together); real balls fall in between.

Sweep the elasticity slider from 1 down to 0 and watch the story unfold: at 1 the carts bounce with kinetic energy intact, at 0 they lock together, and in between energy quietly drains away — while the momentum total holds firm at every setting.

Two dimensions and a worked problem

In a two-dimensional collision — a cue ball striking another at an angle — momentum is a vector, so it is conserved component by component: the total x-momentum before equals the total x-momentum after, and likewise for y. You get one conservation equation per direction. A famous result: when a moving ball elastically strikes an identical stationary ball off-center, the two always separate at exactly 90^\circ.