JOVANA
Library Glossary Getting Started Three Levels Fields How it works Mission
Join the mission
All guides

Interior, Closure, Boundary, and Convergence

Three operations carve every set into inside, edge, and outside; and the epsilon-N definition of a limit transplants, word for word, into any metric space.

Interior, closure, boundary

Given any set A, the interior int(A) is the set of points that sit comfortably inside A — points a with some ball B(a, r) ⊆ A. It is the largest open set contained in A. The closure cl(A) is the smallest closed set containing A; equivalently, it is A together with all points that A presses up against. The boundary ∂A is what is left when you subtract the interior from the closure: ∂A = cl(A) \ int(A) — the skin of the set, the points that are neither safely inside nor safely outside.

Take A = (0, 1] on the real line. Its interior is (0, 1) — the endpoint 1 has no ball staying inside A. Its closure is [0, 1] — the point 0 is pressed against by points of A as close as we like. Its boundary is the two-point set {0, 1}. A point a is a limit point of A if every ball around it contains a point of A other than a itself; the closure is exactly A together with all its limit points.

Convergence, transplanted

On the real line, x_n → L means: for every epsilon > 0 there is an index N so that |x_n − L| < epsilon for all n ≥ N. To define convergence in a metric space we change exactly one symbol — replace |x_n − L| with d(x_n, L). A sequence (x_n) converges to L in (X, d) if for every epsilon > 0 there is N such that d(x_n, L) < epsilon whenever n ≥ N. Equivalently: x_n is eventually inside every ball around L. The entire epsilon-N machinery survives the move intact.

One inheritance is worth proving: limits are unique. The argument is the classic triangle-inequality squeeze, and it works in any metric space because the only tools it uses are the axioms themselves.

Claim: in any metric space a sequence has at most one limit.

Suppose x_n -> L and x_n -> M.  We show L = M.
Fix any epsilon > 0.

From x_n -> L: there is N1 with d(x_n, L) < epsilon/2 for n >= N1.
From x_n -> M: there is N2 with d(x_n, M) < epsilon/2 for n >= N2.

Pick any n >= max(N1, N2).  By the triangle inequality,

      d(L, M) <= d(L, x_n) + d(x_n, M)
              <  epsilon/2 + epsilon/2
              =  epsilon.

So d(L, M) < epsilon for EVERY epsilon > 0.
The only non-negative number smaller than every epsilon is 0,
so d(L, M) = 0, and by the identity axiom L = M.   QED
Uniqueness of limits — pure triangle inequality, valid in every metric space.

Closed sets, sequentially

Convergence gives a second, often more usable description of closedness. A set F is closed if and only if it is sequentially closed: whenever a sequence of points of F converges, its limit also lies in F. This is why “closed” feels like “contains its own limits.” To show a set is closed, a clean strategy is to grab a convergent sequence inside it and prove the limit cannot escape.