JOVANA
Library Glossary Getting Started Three Levels Fields How it works Mission
Join the mission
All guides

Formulas, Word Problems & Solution Sets

Put it all together: rearrange a literal equation to solve for any letter, translate a word problem into an equation and solve it, recognize identities and contradictions, and write every answer cleanly in interval notation.

Rearranging literal equations

A literal equation is one with several letters, such as a formula. Rearranging a formula means solving for one chosen letter while treating the others as if they were known constants. The moves are identical to ordinary solving — inverse operations, both sides — you just carry letters instead of numbers and stop when your target letter stands alone.

Solve the area formula   A = (1/2) b h   for h.

Multiply both sides by 2:
  2A = b h
Divide both sides by b:
  2A / b = h

So  h = 2A / b.
Check the logic: if A = 10 and b = 4, then h = 20/4 = 5,
and (1/2)(4)(5) = 10 = A.  Consistent.
Treat A and b as known; isolate h with the same inverse operations.

Translating a word problem

A word problem is solved by translation, not magic. Name the unknown with a letter, write the relationship the words describe as an equation, solve it, then interpret the answer back in the original units and check it against the story.

  1. Read the question and decide exactly what the unknown is; name it (let x = …).
  2. Translate each relationship into algebra: 'is' becomes =, 'more than' becomes +, 'of' often becomes ×.
  3. Solve the equation by isolating the variable.
  4. Interpret the number in context and check that it answers the actual question.
Word problem: A shirt costs $8 more than twice the price of a cap.
Together they cost $50. Find the price of the cap.

Let c = price of the cap (in dollars).
Shirt = 2c + 8.
Together:  c + (2c + 8) = 50
           3c + 8 = 50
           3c = 42
           c = 14

Cap = $14, shirt = 2(14) + 8 = $36, and 14 + 36 = 50.  Story checks out.
Name the unknown, translate, solve, then interpret in dollars.

Identities, contradictions, and clean answers

Not every linear equation has exactly one solution. If solving collapses the variable and leaves something always true, like 5 = 5, the equation is an identity and every number is a solution. If it leaves something always false, like 5 = 8, it is a contradiction with no solution. Both outcomes are honest answers, not mistakes — recognizing them keeps you from chasing an x that does not exist.

Identity:   2(x + 3) = 2x + 6
  2x + 6 = 2x + 6  ->  0 = 0  (always true)
  Solution set: all real numbers,  (-infinity, infinity).

Contradiction:  x + 1 = x + 4
  1 = 4  (never true)
  Solution set: empty set,  no solution.
When x disappears: always-true means all reals; always-false means none.