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Rational Exponents & Rationalizing the Denominator

The grand unification: a fractional exponent is a root. Once roots are written as powers, all the exponent laws apply to radicals too. We finish with rationalizing — clearing a radical out of a denominator, including the conjugate trick for two-term denominators.

A fraction in the exponent means a root

What should b^(1/2) mean? Demand that the power rule still hold: (b^(1/2))^2 = b^(1/2 · 2) = b^1 = b. So b^(1/2) is a number that squares to b — it’s the square root. In general a rational exponent 1/n is the nth root: b^(1/n) = the nth root of b.

A general fraction m/n combines both: b^(m/n) means take the nth root and raise to the m, in either order. The denominator is the index (the root); the numerator is the power. Reading b^(2/3) as “cube root, then square” keeps the arithmetic small.

9^(1/2)  = sqrt(9) = 3
8^(1/3)  = cube root of 8 = 2
8^(2/3)  = (8^(1/3))^2 = 2^2 = 4      (root first, then square)
16^(3/4) = (16^(1/4))^3 = 2^3 = 8

Negative + fractional:  4^(−1/2) = 1 / 4^(1/2) = 1/2
Denominator = root, numerator = power. Take the root first to keep numbers small.

Rationalizing a one-term denominator

By convention we don’t leave a radical in the denominator. Rationalizing removes it by multiplying the fraction by a clever form of 1. For a single square-root denominator, multiply top and bottom by that same root: the denominator becomes a whole number and the value is unchanged.

  3            3     sqrt(2)     3·sqrt(2)
------  =  ------ · -------  =  ---------
sqrt(2)     sqrt(2)  sqrt(2)        2

   5          5      sqrt(3)    5·sqrt(3)
-------  =  ------ · -------  = ---------
2·sqrt(3)   2·sqrt(3) sqrt(3)       6
Multiply by sqrt(2)/sqrt(2) = 1; sqrt(2)·sqrt(2) = 2 clears the denominator.

Two-term denominators: the conjugate

When the denominator has two terms like 1 + sqrt(2), multiplying by the same root won’t clear it. Instead multiply by the conjugate — the same two terms with the middle sign flipped. The product follows (a+b)(a−b) = a^2 − b^2, and squaring kills the radical.

    1                1        (1 − sqrt(2))
--------- =  --------------- · -------------
1 + sqrt(2)   1 + sqrt(2)       1 − sqrt(2)

denominator: (1)^2 − (sqrt(2))^2 = 1 − 2 = −1

     1 − sqrt(2)
  =  -----------  =  −(1 − sqrt(2))  =  sqrt(2) − 1
        −1
The conjugate 1 − sqrt(2) turns the denominator into 1 − 2 = −1.