the transform of a derivative
This is the single rule that makes the whole Laplace method worth learning. Everything else is supporting cast; this is the star. It says that the operation we most dread in a differential equation — taking a derivative — turns, in the s-domain, into something almost trivial: multiplying by s. That is the magic that converts calculus into algebra.
The first-derivative rule is L{f'(t)} = s F(s) - f(0). In words: the transform of the derivative is s times the transform of the function, minus the starting value f(0). The second-derivative rule builds on it: L{f''(t)} = s^2 F(s) - s f(0) - f'(0). Notice two things. First, each derivative roughly brings down a factor of s out front — that is the 'differentiation becomes multiplication' effect. Second, and crucially, the initial values f(0), f'(0) are subtracted off automatically. They are not an afterthought you bolt on at the end; they enter the equation the moment you transform. This rule comes from applying integration by parts to the defining integral, where the e^(-st) factor at the boundaries produces exactly the f(0) term.
Because of this rule, a differential equation in y(t) — full of y'' and y' — becomes an algebraic equation in Y(s) with the numbers f(0), f'(0) already plugged in. There is no separate step where you 'apply the initial conditions' to pin down arbitrary constants; the Laplace method never produces arbitrary constants in the first place. This is the deep advantage of the method, and this rule is precisely where that advantage is born.
Transform the equation y'' + 3y' + 2y = 0 with y(0) = 1, y'(0) = 0. Using the rules: [s^2 Y - s(1) - 0] + 3[s Y - 1] + 2Y = 0, i.e. (s^2 + 3s + 2) Y - s - 3 = 0. The initial data 1 and 0 are already inside the algebra.
L{f'} = sF(s) - f(0): differentiation becomes multiply-by-s plus the initial value.
Do not forget the f(0) terms — dropping them is the most common error and it silently throws away the initial conditions, giving the wrong solution. Every s pulled down must be paired with the right initial value subtracted off.