The Residue Theorem & the Evaluation of Integrals

the sum-of-all-residues identity

Here is a strikingly clean accounting law: for a nicely behaved function, if you add up all of its residues — every finite singularity plus the residue at infinity — the total is exactly zero. Nothing is left over. It is as though residues were a conserved quantity whose books must always balance across the whole sphere.

The statement: if f is holomorphic on the entire complex plane except for finitely many isolated singularities (so f is rational, or more generally meromorphic on the Riemann sphere), then the sum of Res(f, z_j) over all finite singularities z_j, plus Res(f, infinity), equals 0. The reason is short and elegant. Take a circle |z| = R large enough to enclose every finite singularity. By the residue theorem the integral over that circle equals 2 pi i times the sum of all finite residues. But by the very definition of the residue at infinity, that same integral also equals minus 2 pi i times Res(f, infinity). Setting the two expressions equal and dividing by 2 pi i gives: the sum of all finite residues plus Res(f, infinity) = 0. The point at infinity is not a special exception; it is the one extra entry that closes the ledger.

This identity is genuinely useful, not just pretty. When a rational function has many finite poles but a simple structure at infinity, it is often far less work to compute the single residue at infinity (via w = 1/z) and use the identity to get the sum of all the finite residues in one stroke — which by the residue theorem is the contour integral you wanted. It is the philosophical capstone of residue calculus: on the closed surface of the Riemann sphere there is no 'outside,' so all the local data must sum to nothing.

For f(z) = 1 / (z^2 - 1) = 1/((z-1)(z+1)), the finite residues are 1/2 at z = 1 and -1/2 at z = -1, summing to 0; consistently, the residue at infinity is 0 too, and the total is 0.

Finite residues plus the residue at infinity always sum to zero.

The identity needs f to have only finitely many singularities in the whole plane (meromorphic on the sphere); a function with infinitely many poles, like 1/sin z, does not qualify and the bare identity fails. The minus sign hidden in the definition of the residue at infinity is what makes the total vanish.

Also called
the residue theorem on the spheretotal residue equals zero留數總和為零