Laplace Transform: Discontinuous & Impulse Forcing

piecewise-defined forcing

Real machines are not pushed by a single neat formula for all time. A heater runs at one power, then drops to another; a circuit gets one voltage, then a different one after a switch flips. The driving term changes its rule at certain times — that is piecewise-defined forcing, a function given by one expression on this interval, another on the next.

The classic trap is that a piecewise function looks like several separate problems glued together, and naively you would solve each piece and try to stitch the answers. The Laplace method offers something cleaner: rewrite the whole piecewise forcing as a SINGLE expression using Heaviside steps. If f is g1(t) up to t = a and g2(t) afterward, write f(t) = g1(t) + [g2(t) - g1(t)] u(t - a): the step adds in the 'correction' g2 - g1 only after t = a. Now there is one formula, one transform (using the second shifting theorem on each delayed block), one algebraic solve in the s-domain, and one inverse transform — and the answer automatically comes out continuous and correct across every switch.

This is the everyday workhorse of applied Laplace transforms. Square pulses, staircase inputs, ramps that turn on, sources that shut off — all become tidy sums of steps, and the transform handles the bookkeeping that piecing-by-hand would botch. It is precisely where the Laplace method beats the older guess-and-match methods.

Forcing that is 0 for t < 1, equals t for 1 ≤ t < 3, and is 0 for t ≥ 3 can be written as t·u(t - 1) - t·u(t - 3); rewriting each piece in terms of (t - 1) and (t - 3) makes the transform a routine table lookup.

Two steps carve the active window 1 ≤ t < 3; one formula replaces three cases.

The forcing may jump, but the solution of a well-posed second-order ODE stays continuous (its second derivative may jump). A discontinuous input does not by itself produce a discontinuous response.

Also called
piecewise forcingpiecewise input分段強迫項分段輸入