Limits & continuity

indeterminate form

Imagine a tug of war where both teams pull with enormous, growing force. Knowing only that both forces are 'huge' tells you nothing about who wins — the result depends on the details of how each side grows. An indeterminate form is the limit version of that standoff: a symbolic clash like 0/0 or infinity/infinity where two competing tendencies are fighting, and the bare form alone cannot tell you the answer.

When you try to evaluate a limit by substitution and the expression collapses into one of these patterns, the form is indeterminate: the common ones are 0/0, infinity/infinity, 0 times infinity, infinity minus infinity, plus the exponential cases 1^infinity, 0^0, and infinity^0. The honest reading is 'not yet decided' — the limit might be any finite number, or infinity, or fail to exist, depending on the specific functions. You resolve it by doing more work: factor and cancel, rationalize, divide by the dominant term, or apply L'Hopital's rule (which, for 0/0 or infinity/infinity, replaces the ratio with the ratio of derivatives).

Here is the key distinction people miss: indeterminate is NOT the same as undefined. Something like 1/0 is undefined and signals the function blows up; but 0/0 is indeterminate, meaning it is a question still open. For instance, sin(x)/x and (e^x - 1)/x and x/x all give the form 0/0 at 0, yet their limits are 1, 1, and 1 — while x^2/x gives 0 and x/x^2 gives infinity. Same form, different answers: that is exactly why it earns the name 'indeterminate.'

lim x->0 sin(x)/x = 1 while lim x->0 (1-cos x)/x = 0 (both are 0/0)

Both expressions start as 0/0, yet resolve to different limits — proof that the form alone does not fix the answer.

Indeterminate is not the same as undefined: 1/0 is undefined (the function blows up), but 0/0 is an open question whose limit must be found by other means.

Also called
indeterminate expression未定式不定型