Holomorphic Functions & the Cauchy–Riemann Equations

the Cauchy-Riemann equations as a necessary condition

This is the easy half of the Cauchy-Riemann story: IF f is complex-differentiable at a point, THEN its real and imaginary parts must satisfy u_x = v_y and u_y = -v_x there. The word 'necessary' means these equations are an unavoidable consequence — they are a test every differentiable function has to pass.

The proof is just the difference quotient evaluated along two directions. Since the limit f'(z_0) exists, any way of approaching z_0 must give the same value. Approaching horizontally (z = z_0 + h with h real, h -> 0) yields f'(z_0) = u_x + i v_x. Approaching vertically (z = z_0 + i k with k real, k -> 0, and the step in the denominator being i k) yields f'(z_0) = (u_y + i v_y)/i = v_y - i u_y. Setting the two expressions equal and matching real and imaginary parts gives u_x = v_y and v_x = -u_y.

Used as a test, the necessary condition is a quick way to PROVE a function is NOT holomorphic: just exhibit a point where CR fails. For instance f(z) = z-bar has u = x, v = -y, so u_x = 1 but v_y = -1; the equations fail everywhere, so z-bar is nowhere differentiable. The condition cannot, by itself, prove a function IS differentiable — that needs the sufficient condition.

Test f(z) = |z|^2 = x^2 + y^2 (so u = x^2 + y^2, v = 0): u_x = 2x must equal v_y = 0, forcing x = 0; u_y = 2y must equal -v_x = 0, forcing y = 0. CR holds only at z = 0, so |z|^2 can be differentiable nowhere except possibly the origin.

Necessity gives a fast disproof: find one point where CR fails and differentiability there is dead.

Necessity is one-directional: CR can hold at a point while f still fails to be differentiable there, so this half alone never certifies holomorphy.

Also called
necessity of CR必要條件