the compound Poisson process
Often the events themselves carry a random size, and you care about the running total of those sizes, not just the count. An insurer cares about total claim money, not how many claims; a website cares about total bytes served, not how many requests. The compound Poisson process tracks exactly this: events arrive as a Poisson process, and each event brings along an independent random amount, which you keep adding up.
Formally, let N(t) be a Poisson process of rate lambda, and let Y1, Y2, Y3, ... be independent and identically distributed jump sizes, independent of N. The compound process is the random sum X(t) = Y1 + Y2 + ... + Y_{N(t)} — add up the sizes of all events that have happened by time t (and X(t) = 0 if none have). Both the number of terms AND the terms are random. Its mean is beautifully simple by conditioning: E[X(t)] = E[N(t)] * E[Y] = lambda*t*E[Y]. Its variance follows from the law of total variance and is Var(X(t)) = lambda*t*E[Y^2] (note: the SECOND moment of Y, not its variance — a common slip). So you scale up the per-event statistics by the expected number of events.
This is the standard model of accumulated, lumpy risk. In insurance it is the classical aggregate-claims model; in finance it appears in jump models of asset prices; in inventory it models total demand. Two honest cautions: X(t) is generally NOT Poisson-distributed (it is only Poisson when each Y is exactly 1, i.e. ordinary counting), and its distribution usually has no neat closed form — you reach for its characteristic function or moment generating function, or simulate it. The clean part is the moments, which the conditioning argument hands you immediately.
Claims arrive Poisson at lambda = 5 per day; each claim's size Y has mean E[Y] = 2000 dollars and E[Y^2] = 9,000,000. Total daily claims X(1) have mean 5*2000 = 10,000 dollars and variance 5*9,000,000 = 45,000,000, so a standard deviation of about 6708 dollars. Note we used E[Y^2], not Var(Y).
A random sum: random count times random sizes. E[X(t)] = lambda*t*E[Y], Var = lambda*t*E[Y^2].
The compound total X(t) is NOT Poisson (unless every jump equals 1), and its variance uses E[Y^2], the second moment, not Var(Y).