Electromagnetic Induction & AC

back-EMF

When a motor spins, it fights the very current that is driving it. The turning coil generates its own voltage that pushes back against the supply. That opposing voltage is the back-EMF. It answers a puzzle every motor shows: why does a motor draw less current the faster it spins?

Precisely, a running motor is also a generator: its rotating coil induces an EMF that opposes the applied voltage, exactly as Lenz's law demands. The current is set by the difference between the supply and this back-EMF: I = (V_supply - EMF_back) / R, where R is the coil's resistance. At start-up the coil is not yet turning, so EMF_back = 0 and the current is large; as the motor speeds up, the back-EMF grows and the current falls.

This explains start-up current surges, why a stalled motor overheats (its back-EMF collapses and the current soars), and why motors run efficiently once up to speed. The honest point is that back-EMF is not wasted energy — it is the signature of mechanical work being done; the more work the motor does, the more it is loaded down and the more current it must draw.

A fan motor on 120 V has coil resistance 6 ohm. At start-up, with no back-EMF, the current is 120 / 6 = 20 A. At full speed, with a back-EMF of 108 V, the current is (120 - 108) / 6 = 2 A.

Back-EMF rises with speed, cutting a 20 A start-up surge to 2 A when running.

If a motor jams, the back-EMF disappears and the current can rise high enough to burn out the windings. This is why blocked motors trip breakers, smoke, or blow fuses.

Also called
counter-EMFback electromotive force反抗電動勢